Question:
Let \(f:[-4,2] \rightarrow \R\) be given by \(f(x) = \sqrt{16-x^2}\). Then the range of the function f is
Let \(f:[-4,2] \rightarrow \R\) be given by \(f(x) = \sqrt{16-x^2}\). Then the range of the function f is
Updated On: Jun 10, 2024
- [0,2]
- [0,2√3]
- [0,4]
- [2√3,4]
- [-2,2]
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The Correct Option is C
Solution and Explanation
The correct option is (C): [0,4]
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