The correct answer is (B):
In ∆ABC, AB = 1 cm, BC = 1 cm
As ∠B = 120,
AC2 = 12 + 12 – 2(1) (1) cos (120°) (Cosine rule)
= 12 + 12 + 1 = 3
⇒ AC = √3 cm
The square of side √3 cm will have an area of (√3 )2 = 3 cm2
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$