Let a pair of dice be thrown and the random variable X be the sum of numbers on the two dice. Then. Match List I with List II. List I List II A. P (X = 2) I. $\frac{4}{36}$ B. P (X = 4) II. $\frac{5}{36}$ C. P (X - 5) III. $\frac{1}{36}$ D. P (X - 6) IV. $\frac{3}{36}$ Choose the correct answer from the options given below:

Question

Let a pair of dice be thrown and the random variable X be the sum of numbers on the two dice. Then. Match List I with List II. List I List II A. P (X = 2) I. $\frac{4}{36}$ B. P (X = 4) II.  $\frac{5}{36}$ C. P (X - 5) III.  $\frac{1}{36}$ D. P (X - 6) IV.  $\frac{3}{36}$ Choose the correct answer from the options given below:

cdquestions Admin · Accepted Answer

The correct option is (C): A-III, B-IV, C-I, D-II

Answer

А-I, В-II, С-III, D-IV

Answer

А-II, В-III, С-IV, D-I

Answer

A-III, B-IV, C-I, D-II

Answer

A-IV, B-I, C-II, D-III

List I	List II
A. \(P (\bar{\bigwedge} \cap \bar{B}) = P(\bar{\bigwedge}) . P(\bar{B})\)	I. \(P(A/B) \geq P(A)\)
B. \(A \subset B \) and \(P(B) \neq0\)	II. \(P(A) = P(B)\)
C. \(P(A \bigcup B) = P(A) + P(B)\)	III. A and B are independent events
D. \(P(A\|B) = P (B\|A)\)	IV. A and B are mutually exclusive events

The Correct Option is C

Solution and Explanation

Top Questions on Probability of Random Experiments

Questions Asked in CUET exam

List I	List II
A. P (X = 2)	I. \(\frac{4}{36}\)
B. P (X = 4)	II. \(\frac{5}{36}\)
C. P (X - 5)	III. \(\frac{1}{36}\)
D. P (X - 6)	IV. \(\frac{3}{36}\)