For two events A and B Match List I with List II List I List II A. $P (\bar{\bigwedge} \cap \bar{B}) = P(\bar{\bigwedge}) . P(\bar{B})$ I. $P(A/B) \geq P(A)$ B. $A \subset B $ and $P(B) \neq0$ II. $P(A) = P(B)$ C. $P(A \bigcup B) = P(A) + P(B)$ III. A and B are independent events D. $P(A|B) = P (B|A)$ IV. A and B are mutually exclusive events Choose the correct answer from the options given below:

Question

For two events A and B Match List I with List II List I List II A. $P (\bar{\bigwedge} \cap \bar{B}) = P(\bar{\bigwedge}) . P(\bar{B})$ I.  $P(A/B) \geq P(A)$ B.  $A \subset B $  and  $P(B) \neq0$ II.  $P(A) = P(B)$ C.  $P(A \bigcup B) = P(A) + P(B)$ III. A and B are independent events D.  $P(A|B) = P (B|A)$ IV. A and B are mutually exclusive events Choose the correct answer from the options given below:

cdquestions Admin · Accepted Answer

The correct option is (B): А-III, В-I, C-IV, D-II

Answer

A-III, В-II, C-IV, D-I

Answer

А-III, В-I, C-IV, D-II

Answer

A-IV, B-II, C-III, D-I

Answer

A-IV, B-I, C-III, D-II

List I	List II
A. \(P (\bar{\bigwedge} \cap \bar{B}) = P(\bar{\bigwedge}) . P(\bar{B})\)	I. \(P(A/B) \geq P(A)\)
B. \(A \subset B \) and \(P(B) \neq0\)	II. \(P(A) = P(B)\)
C. \(P(A \bigcup B) = P(A) + P(B)\)	III. A and B are independent events
D. \(P(A\|B) = P (B\|A)\)	IV. A and B are mutually exclusive events

List I	List II
A. P (X = 2)	I. \(\frac{4}{36}\)
B. P (X = 4)	II. \(\frac{5}{36}\)
C. P (X - 5)	III. \(\frac{1}{36}\)
D. P (X - 6)	IV. \(\frac{3}{36}\)

The Correct Option is B

Solution and Explanation

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