Question:

Let A A be any n×m n \times m matrix, where m>n m>n . Which of the following statements is/are TRUE about the system of linear equations Ax=0 Ax = 0 ?

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For underdetermined systems (( m>n )), the null space dimension is key to determining the number of linearly independent solutions.
Updated On: Jan 22, 2025
  • There exist at least mn m - n linearly independent solutions to this system
  • There exist mn m - n linearly independent vectors such that every solution is a linear combination of these vectors
  • There exists a non-zero solution in which at least mn m - n variables are 0
  • There exists a solution in which at least n n variables are non-zero
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The Correct Option is A

Solution and Explanation

Step 1: Analyze the null space of A A .
For an n×m n \times m matrix A A , the rank-nullity theorem states: Nullity(A)=mRank(A). \text{Nullity}(A) = m - \text{Rank}(A). Given m>n m>n , the rank of A A is at most n n , so the nullity is at least mn m - n . Step 2: Validate the options.
Option (1): There are at least mn m - n linearly independent solutions in the null space of A A , which is correct.
Option (2): While mn m - n vectors span the null space, this does not imply they are solutions to Ax=0 Ax = 0 . Incorrect.
Option (3): There is no guarantee that mn m - n variables in the solution are 0. Incorrect.
Option (4): There is no guarantee that at least n n variables are non-zero in the solution. Incorrect. Final Answer: (1) \boxed{(1)}
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