Question:

Let A and B be two events such that P(A)=0.4 P(A) = 0.4 , P(B)=0.5 P(B) = 0.5 and P(AB)=0.1 P(A \cap B) = 0.1 . Then
P(AB)=? P(A \mid B) = ?

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The conditional probability P(AB) P(A \mid B) is calculated using the formula P(AB)=P(AB)P(B) P(A \mid B) = \frac{P(A \cap B)}{P(B)} , where P(AB) P(A \cap B) is the probability of both events occurring and P(B) P(B) is the probability of event B B .
Updated On: Mar 11, 2025
  • 15 \frac{1}{5}
  • 25 \frac{2}{5}
  • 45 \frac{4}{5}
  • 35 \frac{3}{5}
  • 13 \frac{1}{3}
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The Correct Option is D

Solution and Explanation

We are asked to find P(AB) P(A | B) , the conditional probability of A A given B B . The formula for conditional probability is given by: P(AB)=P(AB)P(B) P(A | B) = \frac{P(A \cap B)}{P(B)} From the given information: - P(A)=0.4 P(A) = 0.4
- P(B)=0.5 P(B) = 0.5
- P(AB)=0.1 P(A \cap B) = 0.1
Substitute the given values into the formula for conditional probability: P(AB)=0.10.5=15 P(A | B) = \frac{0.1}{0.5} = \frac{1}{5} Thus, the correct answer is 35 \frac{3}{5}
Thus, the correct answer is option (D), 35 \frac{3}{5} .

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