Question:
Let 2π§=-3+β3 π , π = ββ1. Then 2z 8 is equal to
Let 2π§=-3+β3 π , π = ββ1. Then 2z 8 is equal to
Updated On: Oct 1, 2024
- \(β81 (1+\sqrt3 π )\)
- 81 (β1 + \(\sqrt3 π\) )
- \(81 (\sqrt3 + π )\)
- \(9 (β\sqrt3 + π )\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): 81 (β1 + \(\sqrt3 π\) )
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