\(KI\)
\(Pbl_2\)
When lead nitrate reacts with potassium iodide, a double displacement reaction occurs. The products formed are lead iodide (PbI$_2$) and potassium nitrate (KNO$_3$). Lead iodide is insoluble in water and forms a bright yellow precipitate. This yellow color is characteristic of solid PbI$_2$, and none of the other reactants or products are yellow.
The correct option is (C): Pbl
\(\text{Reaction of aniline with conc. HNO}_3 \text{ and conc. H}_2\text{SO}_4 \text{ at 298 K will produce 47\% of:}\)