Question:
Lead nitrate on reaction with potassium iodide gives yellow precipitate. The yellow color is due to
\(Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + 2KNO_3\)
Lead nitrate on reaction with potassium iodide gives yellow precipitate. The yellow color is due to
\(Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + 2KNO_3\)
\(Pb(NO_3)_2 + 2KI \rightarrow PbI_2 + 2KNO_3\)
Updated On: Apr 7, 2025
- \(Pb(NO_3)_2\)
\(KI\)
\(Pbl_2\)
- \(KNO_3\)
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The Correct Option is C
Solution and Explanation
When lead nitrate reacts with potassium iodide, a double displacement reaction occurs. The products formed are lead iodide (PbI$_2$) and potassium nitrate (KNO$_3$). Lead iodide is insoluble in water and forms a bright yellow precipitate. This yellow color is characteristic of solid PbI$_2$, and none of the other reactants or products are yellow.
The correct option is (C): Pbl
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