खालीलपैकी कोणत्याही दोन वाक्प्रचारांचा अर्थ सांगून वाक्यात उपयोग करा :
कंठस्नान घालणे
खालीलपैकी कोणत्याही दोन वाक्प्रचारांचा अर्थ सांगून वाक्यात उपयोग करा :
कंठस्नान घालणे
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Solution and Explanation
वाक्यात उपयोग: तिच्या उत्कृष्ट कामगिरीला पाहून तिला कंठस्नान घालण्यात आले.
Top Questions on Grammar
আবেগসূচক বাক্যের একটি উদাহরণ দাও।
“আকাশবাণী”— সমাসবদ্ধ পদটির ব্যাসবাক্যসহ সমাসের নাম লেখো।
“হয় বাংলা পড়ো, নয় ইংরেজি পড়ো”— যৌগিক বাক্যে পরিবর্তন করো।
বাক্য নির্ণয়ের শর্তগুলি সংক্ষেপে উল্লেখ করো।
অলাপ সমাস কাকে বলে?
Questions Asked in Maharashtra Class X Board exam
- Appreciation of the poem:
Read the following poem and write an appreciation of it with the help of the points given below:
Stopping by Woods on a Snowy Evening
Whose woods these are I think I know.
His house is in the village, though;
He will not see me stopping here
To watch his woods fill up with snow
My little horse must think it queer
To stop without a farmhouse near
Between the woods and frozen lake
The darkest evening of the year.
He gives his harness bells a shake
To ask if there is some mistake.
The only other sound’s the sweep
Of easy wind and downy flake.
The woods are lovely, dark and deep,
But I have promises to keep,
And miles to go before I sleep,
And miles to go before I sleep.
Robert Frost
- Maharashtra Class X Board - 2025
- Reading Comprehension
- Pick out the infinitive from the following sentence :
He was asking to go for the concert.- Maharashtra Class X Board - 2025
- Grammar and Language Usage
- Out of the following which is a Pythagorean triplet ?
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\).
- Maharashtra Class X Board - 2025
- Properties of Triangles
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.