खालील वाक्यात योग्य विमर्शिकेची स्थान वाक्य पूर्ण लिहा:
खालील वाक्यात योग्य विमर्शिकेची स्थान वाक्य पूर्ण लिहा:
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Solution and Explanation
- येथे "कारण" म्हणजे एक कनेक्टर (conjunction) आहे जो कारण दर्शवतो. यामध्ये "मी पदं समाचं सांगीतल कारण" म्हणजे "मी कारण सांगितले" किंवा "मी समाचं कारण सांगितले" हे स्पष्ट करण्याचा एक उद्दीष्ट आहे.
वाक्य 2: मी तुम्हाला खूप जवळून पाहिलं.
- येथे "जवळून" हे शब्द एक प्रकारे सूचित करतं की, 'समीप' किंवा 'अधिक जवळून' पाहणे. ह्या वाक्यात हे सूचित करतं की 'मी तुम्हाला अधिक तपशिलांत पाहिलं.'
Top Questions on Grammar
আবেগসূচক বাক্যের একটি উদাহরণ দাও।
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“হয় বাংলা পড়ো, নয় ইংরেজি পড়ো”— যৌগিক বাক্যে পরিবর্তন করো।
বাক্য নির্ণয়ের শর্তগুলি সংক্ষেপে উল্লেখ করো।
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Questions Asked in Maharashtra Class X Board exam
- Appreciation of the poem:
Read the following poem and write an appreciation of it with the help of the points given below:
Stopping by Woods on a Snowy Evening
Whose woods these are I think I know.
His house is in the village, though;
He will not see me stopping here
To watch his woods fill up with snow
My little horse must think it queer
To stop without a farmhouse near
Between the woods and frozen lake
The darkest evening of the year.
He gives his harness bells a shake
To ask if there is some mistake.
The only other sound’s the sweep
Of easy wind and downy flake.
The woods are lovely, dark and deep,
But I have promises to keep,
And miles to go before I sleep,
And miles to go before I sleep.
Robert Frost
- Maharashtra Class X Board - 2025
- Reading Comprehension
- Pick out the infinitive from the following sentence :
He was asking to go for the concert.- Maharashtra Class X Board - 2025
- Grammar and Language Usage
- Out of the following which is a Pythagorean triplet ?
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\).
- Maharashtra Class X Board - 2025
- Properties of Triangles
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.