काव्यसौंदर्य
'आज पन्नास वर्षांनी अनुभवतोय सूर्यफुले तुझा ध्यास घेतायत बिगूल प्रतीक्षा करतोय चवदार तळ्याचं पाणी, तेही आता थंड झालंय'.
या ओळीतील विचारसौंदर्य स्पष्ट करा.
काव्यसौंदर्य
'आज पन्नास वर्षांनी अनुभवतोय सूर्यफुले तुझा ध्यास घेतायत बिगूल प्रतीक्षा करतोय चवदार तळ्याचं पाणी, तेही आता थंड झालंय'.
या ओळीतील विचारसौंदर्य स्पष्ट करा.
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Solution and Explanation
Top Questions on Poetry
“ক্ষমা করো”— এই উক্তির মধ্যে দিয়ে কবি কী মনোভাব প্রকাশ পেয়েছে?
“ক্ষমা করো”— এই উক্তির মধ্যে দিয়ে কবি কী মনোভাব প্রকাশ পেয়েছে?
“ধূসরলালসা” কবিতার উৎসগ্রন্থ —
“আমি বারো তারিখ ধরেছি মানুষ”— কবিতার মানুষটি কে ?
- Why was Kothamangalam Subbu considered No. 2 in Gemini Studios? (Poets and Pancakes)
Questions Asked in Maharashtra Class X Board exam
- Appreciation of the poem:
Read the following poem and write an appreciation of it with the help of the points given below:
Stopping by Woods on a Snowy Evening
Whose woods these are I think I know.
His house is in the village, though;
He will not see me stopping here
To watch his woods fill up with snow
My little horse must think it queer
To stop without a farmhouse near
Between the woods and frozen lake
The darkest evening of the year.
He gives his harness bells a shake
To ask if there is some mistake.
The only other sound’s the sweep
Of easy wind and downy flake.
The woods are lovely, dark and deep,
But I have promises to keep,
And miles to go before I sleep,
And miles to go before I sleep.
Robert Frost
- Maharashtra Class X Board - 2025
- Reading Comprehension
- Pick out the infinitive from the following sentence :
He was asking to go for the concert.- Maharashtra Class X Board - 2025
- Grammar and Language Usage
- Out of the following which is a Pythagorean triplet ?
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\).
- Maharashtra Class X Board - 2025
- Properties of Triangles
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.