In a triangle, the sum of the lengths of either two sides is always greater than the third side.
(i) Given that, the sides of the triangle are \(2 \;cm, 3 \;cm, 5 \;cm\).
It can be observed that,
\(2 + 3 = 5\) \(cm\)
However, \(5\) \(cm\) = \(5\) \(cm\)
Hence, this triangle is not possible.
(ii) Given that, the sides of the triangle are \(3\; cm, 6\; cm, 7 \;cm\).
Here, \(3 + 6 = 9\) \(cm\) \(>\) \(7\) \(cm\)
\(6 + 7 = 13 \) \(cm \) \(>\) \(3\) \(cm\) \(3 +7\)
= \(10\) \(cm\) \(>\) \(6\) \(cm\)
Hence, this triangle is possible.
(iii) Given that, the sides of the triangle are \(6\; cm, 3 \;cm, 2\; cm\).
Here, \(6 + 3 = 9\) \(cm\) \(>\) \(2\) \(cm\)
However, \(3 + 2 = 5\) \(cm\) \(<\) \(6\) \(cm\)
Hence, this triangle is not possible.
Write equations for the following statements:
(i) The sum of numbers x and 4 is 9.
(ii) 2 subtracted from y is 8.
(iii) Ten times a is 70.
(iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15.
(vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30