Question:

Ionic radii of

Updated On: Jun 14, 2022
  • $Ti^{4+}$
  • $^{35}_{}CI^- < \, ^{37}_{}CI^-$
  • $ K^+ > CI^-$
  • $P^{3+} > P^{5+}$
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The Correct Option is D

Solution and Explanation

(a) $Ti^{4+} > Mn^{7+}$ is the correct order of size due to lower positive charge on $Ti^{4+}$.
(b) $^{35}_{}CI^- < \, ^{37}_{}CI^-$ : Isotopes with same charge have same size because isotopes differ in compositions of nuclei which
do not affect the atomic/ionic radius.
(c) $K^+ < Cl^-$ is the correct order. Among isoelectronic species, anion has greater size than cation.
(d) $P^{3+} > P^{5+}$ is the correct order. For the same elements, lower the positive charge, larger the ions
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Concepts Used:

Haloalkanes and Haloarenes - Classification

Classification of Haloalkanes and Haloarenes are as follows:

Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:

These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;

  • Monohaloalkane
  • Dihaloalkane
  • Trihaloalkane

Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)

This class includes:

  • Alkyl halides or haloalkanes (R—X)
  • Allylic halides
  • Benzylic halides

Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond

This class includes:

  • Vinylic halides
  • Aryl halides