Question:
\(\displaystyle \int_{-1}^{1} x^{17}\,dx=\) ?
\(\displaystyle \int_{-1}^{1} x^{17}\,dx=\) ?
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Any odd power of $x$ integrates to $0$ over $[-a,a]$.
Updated On: Oct 17, 2025
- \(0\)
- \(1\)
- \(\dfrac{3}{17}\)
- \(\dfrac{14}{3}\)
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The Correct Option is A
Solution and Explanation
\(x^{17}\) is an odd function. On symmetric limits \([-1,1]\), the positive and negative areas cancel: integral is \(0\).
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