We are asked to integrate the following expression:
\[
I = \int \frac{dx}{\sin x - \cos x + \sqrt{2}}.
\]
Step 1: Simplifying the expression.
First, we simplify the expression by recognizing a standard trigonometric identity. Start by rewriting \( \sin x - \cos x \) in a form that makes it easier to integrate. We can express \( \sin x - \cos x \) as follows:
\[
\sin x - \cos x = \sqrt{2} \left( \sin \left( x - \frac{\pi}{4} \right) \right).
\]
Thus, the original integral becomes:
\[
I = \int \frac{dx}{\sqrt{2} \sin \left( x - \frac{\pi}{4} \right) + \sqrt{2}}.
\]
Step 2: Substitution.
Now, factor out \( \sqrt{2} \) from the denominator:
\[
I = \int \frac{dx}{\sqrt{2} \left( \sin \left( x - \frac{\pi}{4} \right) + 1 \right)}.
\]
Next, perform the substitution \( u = \frac{x}{2} + \frac{\pi}{8} \), which leads to \( du = \frac{dx}{2} \). This transforms the integral into:
\[
I = \int \frac{2 du}{\sqrt{2} \cdot \sin \left( u \right)}.
\]
Step 3: Applying standard integral.
The integral of the form \( \int \frac{du}{\sin u + 1} \) is a standard result:
\[
I = \frac{1}{\sqrt{2}} \cot \left( u \right) + C.
\]
Substitute \( u = \frac{x}{2} + \frac{\pi}{8} \) back into the equation:
\[
I = \frac{1}{\sqrt{2}} \cot \left( \frac{x}{2} + \frac{\pi}{8} \right) + C.
\]
Step 4: Conclusion.
Thus, the integral evaluates to:
\[
\boxed{\frac{1}{\sqrt{2}} \cot \left( \frac{x}{2} + \frac{\pi}{8} \right) + C}.
\]
Therefore, the correct answer is (c).