Question:

IndiaSMart is a retail shop that accepts either a Rupay credit card, or a Visa credit card. 31 percent of IndiaSMart’s customers carry a Rupay credit card, 44 percent of its customers carry a Visa credit card, while 18 percent of its customers carry a Rupay credit card as well as a Visa credit card. What is the probability that a customer carries at least one of the two, i.e. either a Rupay or a Visa credit card?

Show Hint

To find the probability of a union of two events, use the formula: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).
Updated On: Nov 21, 2025
  • 0.75
  • 0.93
  • 0.57
  • 0.49
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Understand the problem

We are looking for the probability that a customer carries at least one of the two credit cards (Rupay or Visa). This is the union of two events, so we use the formula for the union of two sets:

\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]

Where:

  • P(A) is the probability of carrying a Rupay card (0.31),
  • P(B) is the probability of carrying a Visa card (0.44),
  • P(A ∩ B) is the probability of carrying both cards (0.18).

Step 2: Apply the formula

Substitute the given values into the formula:

\[ P(A \cup B) = 0.31 + 0.44 - 0.18 = 0.57 \]

Thus, the probability that a customer carries at least one of the two credit cards is 0.57.

Was this answer helpful?
0
0

Questions Asked in GATE XH-C1 exam

View More Questions