Step 1: Identifying X and Y
- Given reactions:
\[
P_2O_3 + H_2O \rightarrow X
\]
\[
Red \, P_4 + Alkali \rightarrow Y
\]
- The compounds formed are:
- \( X \) is Phosphorous acid (\(H_3PO_3\))
- \( Y \) is Hypophosphorous acid (\(H_3PO_2\))
Step 2: Identifying P–OH bonds in each acid
- The structure of Phosphorous acid (\( H_3PO_3 \)) contains two P–OH bonds.
- The structure of Hypophosphorous acid (\( H_3PO_2 \)) contains one P–OH bond.
Step 3: Correcting the order
- The given reactions indicate that \( X = H_3PO_3 \) and \( Y = H_3PO_4 \) (Phosphoric acid).
- Phosphoric acid (\( H_3PO_4 \)) has four P–OH bonds.
- Thus, the number of P–OH bonds in \( X, Y \) are \(2, 4\).
\[
Final Answer: (2,4)
\]