Question

In Young's double slit experiment, the intensity of light at a point on the screen where the path difference is \( \lambda \) is:

• A. 1/4
• B. 1/3
• C. 1/2
• D. 1

Hint:

In Young's double slit experiment, the intensity varies depending on the path difference between the slits.

Answer 1

The Correct Option is A

Step 1: Intensity in Young's double slit experiment.
The intensity of light in a double slit experiment is given by the formula: \[ I = I_0 \cos^2 \left( \frac{\pi d \sin \theta}{\lambda} \right) \] where \( I_0 \) is the maximum intensity and \( \lambda \) is the wavelength of light.
Step 2: Explanation.
At a point where the path difference is \( \lambda \), the intensity is reduced to 1/4 of the maximum intensity.
Final Answer: \[ \boxed{\frac{1}{4}} \]