Question:

In which of the following molecules $S$ atom does not assume $sp ^{3}$ hybridsation?

Updated On: Jan 30, 2025
  • $SO_4^{2-}$
  • $SF_4$
  • $SF_2$
  • $SF_8$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

In $SO _{4}^{2-} \Rightarrow bp =4, lp =0 $
$ \therefore$ hybridisation $sp ^{3}$
In SF $_{4} \Rightarrow bp =4, lp =1 $
$ \therefore$ hybridisation $sp ^{3} d$
In $SF _{2} \Rightarrow bp =2, lp =2 $
$\therefore$ hybridisation $sp ^{3}$
In $S _{8} \Rightarrow bp =2, lp =2 $
$ \therefore$ hybridisation $sp ^{3}$
Thus, only $SF _{4}$ does not have $sp ^{3}$ hybridisation.
Was this answer helpful?
0
0

Top Questions on sulphur

View More Questions