Question:
In which of the following, homolytic bond fission takes place ?
In which of the following, homolytic bond fission takes place ?
Updated On: Apr 13, 2024
- Alkaline hydrolysis of ethyl chloride
- Addition of HBr to double bond
- Free radical chlorination of methane
- Nitration of Benzene
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The Correct Option is C
Solution and Explanation
Free radical chlorination of methane Initiation
(1) $Cl_2 {->[\text{Light}]} 2Cl^{\bullet}$
Propagation
(2) $ Cl + CH_4 \rightarrow HCl + \overset{\bullet}{C}H_3$
(3)$CH_3 + Cl_2 \rightarrow CH_3Cl + Cl^{\bullet}$
Termination
(4) $2Cl^{\bullet} \rightarrow Cl_2$
$Cl \bullet + \bullet CH_3 \rightarrow CH_3Cl$
$2. CH_3 \rightarrow CH_3CH_3$
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Concepts Used:
Organic Chemistry – Some Basic Principles and Techniques - Reaction Mechanism
SN1 Reaction Mechanism:
SN1 reaction mechanism takes place by following three steps –
- Formation of carbocation
- Attack of nucleophile
- Deprotonation
SN2 Reaction Mechanism:
The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.
Electrophilic Aromatic Substitution Reaction Mechanism:
The mechanism of an electrophilic aromatic substitution reaction contains three main components which are:
- A new sigma bond from C=C is formed during the reaction in the arene nucleophile.
- Due to the breaking of the C-H sigma bond, a proton is removed.
- The C=C bond is reformed and it restores the aromaticity of the compound.
Electrophilic Substitution Reaction Mechanism:
The electrophilic substitution reaction mechanism is composed of three steps, which will be discussed more below.
- Electrophile Generation
- Carbocation Formation
- Proton Removal