Step 1: Identify the Given Vectors Let the position vectors of the vertices be: \[ \mathbf{P} = 4\hat{i} + 3\hat{j} + 6\hat{k}, \quad \mathbf{Q} = 3\hat{i} + \hat{j} + 3\hat{k}, \quad \mathbf{R} = 3\hat{i} + \hat{j} + 3\hat{k} \] We need to find the position vector of the point where the angle bisector of \( \angle P \) meets the line segment \( QR \).
Step 2: Using the Angle Bisector Theorem By the angle bisector theorem, the point \( D \) dividing \( QR \) in the ratio \( PQ : PR \) lies on the line joining \( Q \) and \( R \). Let \( D \) be the point of intersection. By the angle bisector theorem: \[ \frac{QD}{DR} = \frac{PQ}{PR} \] From the given position vectors: \[ PQ = |\mathbf{Q} - \mathbf{P}| = |(3\hat{i} + \hat{j} + 3\hat{k}) - (4\hat{i} + 3\hat{j} + 6\hat{k})| = |(-\hat{i} - 2\hat{j} - 3\hat{k})| = \sqrt{(-1)^2 + (-2)^2 + (-3)^2} = \sqrt{14} \] \[ PR = |\mathbf{R} - \mathbf{P}| = |(3\hat{i} + \hat{j} + 3\hat{k}) - (4\hat{i} + 3\hat{j} + 6\hat{k})| = |(-\hat{i} - 2\hat{j} - 3\hat{k})| = \sqrt{14} \] Since \( PQ = PR \), the ratio is 1:1. Thus, the point \( D \) is the midpoint of \( QR \).
Step 3: Finding the Midpoint By the midpoint formula, \[ \mathbf{D} = \frac{\mathbf{Q} + \mathbf{R}}{2} \] \[ \mathbf{D} = \frac{(3\hat{i} + \hat{j} + 3\hat{k}) + (3\hat{i} + \hat{j} + 3\hat{k})}{2} \] \[ \mathbf{D} = \frac{(6\hat{i} + 2\hat{j} + 6\hat{k})}{2} \] \[ \mathbf{D} = 3\hat{i} + \hat{j} + 3\hat{k} \]
Step 4: Final Answer
Arrange the following in increasing order of their pK\(_b\) values.
What is Z in the following set of reactions?
Acetophenone can be prepared from which of the following reactants?
What are \(X\) and \(Y\) in the following reactions?
What are \(X\) and \(Y\) respectively in the following reaction?