Question

In the series of reaction \[ \text{C}_6\text{H}_5\text{NH}_2 \xrightarrow{\text{NaNO}_2/\text{HCl}} X \quad \text{and} \quad X \xrightarrow{\text{HNO}_3, \text{H}_2\text{O}} Y + \text{N}_2 + \text{HCl}, \] X and Y are respectively:

• A. \( \text{C}_6\text{H}_5\text{N} = \text{N - C}_6\text{H}_5 \)
• B. \( \text{C}_6\text{H}_5\text{N}_2\text{C}_6\text{H}_5 \)
• C. \( \text{C}_6\text{H}_5\text{N}_2\text{C}_6\text{H}_4 \)
• D. \( \text{C}_6\text{H}_5\text{NO}_2\text{C}_6\text{H}_6 \)

Hint:

Diazotization of aniline with nitrous acid forms a diazonium ion that can undergo substitution reactions, such as with nitro groups.

Answer 1

The Correct Option is B

Step 1: The reaction of aniline with nitrous acid leads to diazotization to form a diazonium salt.
Step 2: On further reaction with HNO₃, a substitution reaction occurs, producing a compound with a nitro group attached to the phenyl ring.

Final Answer: \[ \boxed{\text{C}_6\text{H}_5\text{N}_2\text{C}_6\text{H}_5} \]