Question:

In the reaction of sulfur with concentrated sulfuric acid, the oxidised product is X and reduced product is Y. X and Y are respectively:

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In reactions involving sulfur and sulfuric acid, the products \( {SO}_2 \) and \( {H}_2{S} \) are formed, with sulfur undergoing both oxidation and reduction.
Updated On: Mar 25, 2025
  • \( {SO}_3, {SO}_2 \)
  • \( {SO}_2, {SO}_2 \)
  • \( {SO}_2, {H}_2{S} \)
  • \( {SO}_2, {H}_2{O} \)
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The Correct Option is B

Solution and Explanation

When sulfur reacts with concentrated sulfuric acid, sulfur undergoes oxidation and reduction. The reaction is: \[ {S} + {H}_2{SO}_4 \rightarrow {SO}_2 + {H}_2{S} \] In this reaction:
- Sulfur (S) is oxidized to \( {SO}_2 \), which is the oxidized product (X).
- The sulfur (S) is also reduced to \( {SO}_2 \), which is the reduced product (Y).
Step 1: The sulfur reacts with sulfuric acid to form \( {SO}_2 \) as both the oxidized and reduced product. This is because sulfur in the reaction can simultaneously undergo oxidation and reduction. 
Step 2: Therefore, the correct answer is \( {SO}_2, {SO}_2 \), corresponding to option (2).

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