\( 8 \, \text{mol} \)
\( 4 \, \text{mol} \)
Given reaction:
\( 2H_2 + O_2 \rightarrow 2H_2O \)
The balanced equation tells us that for every 2 moles of \( H_2 \) (hydrogen), 2 moles of \( H_2O \) (water) are produced.
From the balanced equation: \( 2 \, \text{mol} \, H_2 \rightarrow 2 \, \text{mol} \, H_2O \)
Therefore, if 4 moles of hydrogen (\( H_2 \)) react, the number of moles of water produced will be:
\[ \text{moles of } H_2O = \left( \frac{2 \, \text{mol} \, H_2O}{2 \, \text{mol} \, H_2} \right) \times 4 \, \text{mol} \, H_2 = 4 \, \text{mol} \, H_2O \]
The number of moles of water produced is \( \boxed{4 \, \text{mol}} \)
If 0.01 mol of $\mathrm{P_4O_{10}}$ is removed from 0.1 mol, then the remaining molecules of $\mathrm{P_4O_{10}}$ will be: