Question:
In the reaction $2 A+B \rightarrow A_{2} B$, if the concentration of $A$ is doubled and that of $B$ is halved, then the rate of reaction will
In the reaction $2 A+B \rightarrow A_{2} B$, if the concentration of $A$ is doubled and that of $B$ is halved, then the rate of reaction will
Updated On: Jun 8, 2024
- increase by 4 times
- decrease by 2 times
- increase by 2 times
- remains the same
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The Correct Option is C
Solution and Explanation
For the reaction: $2 A+B \rightarrow A_{2} B r=k[A]^{2}[B]$
If concentration of $A$ is doubled and that of $B$ is halved, then
$r'=[2 A]^{2}\left[\frac{B}{2}\right]$
$2 k[A]^{2}[B] r'=2 r$
Hence, if the concentration of
[A] is doubled and
[B] is halved, then rate of reaction increases by 2 times.
If concentration of $A$ is doubled and that of $B$ is halved, then
$r'=[2 A]^{2}\left[\frac{B}{2}\right]$
$2 k[A]^{2}[B] r'=2 r$
Hence, if the concentration of
[A] is doubled and
[B] is halved, then rate of reaction increases by 2 times.
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Concepts Used:
Rate of a Chemical Reaction
The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.
Consider the reaction A → B,
Rate of the reaction is given by,
Rate = −d[A]/ dt=+d[B]/ dt
Where, [A] → concentration of reactant A
[B] → concentration of product B
(-) A negative sign indicates a decrease in the concentration of A with time.
(+) A positive sign indicates an increase in the concentration of B with time.
Factors Determining the Rate of a Reaction:
There are certain factors that determine the rate of a reaction:
- Temperature
- Catalyst
- Reactant Concentration
- Chemical nature of Reactant
- Reactant Subdivision rate