{"@context":"https://schema.org/","@type":"Quiz","dateCreated":"2024-03-21T05:57:33.578Z","dateModified":"2025-03-12T12:04:33.874Z","typicalAgeRange":"11-18","educationalLevel":"CUET (PG)","assesses":"Mathematics - Power series solutions for ordinary points","educationalAlignment":[{"@type":"AlignmentObject","alignmentType":"educationalTopic","targetName":"Power series solutions for ordinary points"},{"@type":"AlignmentObject","alignmentType":"educationalSubject","targetName":"Mathematics"},{"@type":"AlignmentObject","alignmentType":"educationalExam","targetName":"CUET (PG)"}],"name":"Quiz about Power series solutions for ordinary points","about":{"@type":"Thing","name":"Mathematics - Power series solutions for ordinary points"},"hasPart":[{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"intermediate","name":"Question About Power series solutions for ordinary points","text":"In the neighborhood of z = 1, the function f(z) has a power series expansion of the form f(z) = 1+(1-z)+(1-z) 2 + .... then f(z) is}","encodingFormat":"text/markdown","comment":{"@type":"Comment","text":"\"\""},"suggestedAnswer":[{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

\\(\\frac{1}{z}\\)

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":1,"encodingFormat":"text/markdown","text":"

\\(\\frac{-1}{z-2}\\)

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":2,"encodingFormat":"text/markdown","text":"

\\(\\frac{1}{2z-1}\\)

","comment":{"@type":"Comment","text":"\"\""}},{"@type":"Answer","position":3,"encodingFormat":"text/markdown","text":"

\\(\\frac{z-1}{z+1}\\)

","comment":{"@type":"Comment","text":"\"\""}}],"acceptedAnswer":{"@type":"Answer","position":0,"encodingFormat":"text/markdown","text":"

\\(\\frac{1}{z}\\)

","comment":{"@type":"Comment","text":"\"\""},"answerExplanation":{"@type":"comment","text":"The correct answer is(A): \\(\\frac{1}{z}\\)"}}}]}

In the neighborhood of z = 1, the function f(z) has a power series expansion of the form f(z) = 1+(1-z)+(1-z)2 + .... then f(z) is

The Correct Option is A

Solution and Explanation

Questions Asked in CUET PG exam

In the neighborhood of z = 1, the function f(z) has a power series expansion of the form f(z) = 1+(1-z)+(1-z)² + .... then f(z) is