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in the kjeldahl s method for estimation of nitroge
Question:
In the Kjeldahl's method for estimation of nitrogen present in a soil sample, ammonia evolved from
$0.75\, g$
of sample neutralized
$10\, mL$
of
${1 \, M \, H_2SO_4}$
. The percentage of nitrogen in the soil is :
NEET (UG) - 2014
NEET (UG)
Updated On:
Jul 20, 2024
37.33
45.33
35.33
43.33
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The Correct Option is
A
Solution and Explanation
$\because \; M \times V (ml) = m \; mol$
$10 \; m \; mol \; {H_2SO_4 } = 20 \; m \; mol \; of \; {NH_3}$
${[H_2SO_4 + 2NH_3 -> (NH_4)_2 SO_4]}$
${1 \; mol \; NH_3}$
contains 14 g nitrogen
${20 \times 10^{-3} \; mol \; NH_3}$
contains
${14 \times 20 \times 10^{-3}}$
nitrogen
0.75 g of sample contains
$\% $
Nitrogen
$ = \frac{14 \times 20 \times 10^{-3}}{0.75} \times 100 = 37.33 \%$
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