Question:

In the JK flip-flop shown, initial Q = 0. Find output sequence at Q after each clock if \( J = K = 1 \):
 JK flip-flop

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JK Flip-Flop with J = K = 1 → toggles on every clock pulse.
Updated On: Jun 12, 2025
  • 0000…
  • 1010…
  • 1111…
  • 1000…
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The Correct Option is C

Solution and Explanation

The JK flip-flop is a type of digital storage device that changes state on the triggering edge of the clock signal. It consists of two inputs, J and K, and one output, Q. Initially, Q = 0. The behavior of the JK flip-flop when J = K = 1 is a toggle operation, meaning the output Q will flip from 0 to 1 or from 1 to 0 on each clock pulse.
Given J = K = 1, apply the following logic at each clock pulse:
  1. Initial State: Q = 0
  2. 1st Clock Pulse: Since J = K = 1, flip Q from 0 to 1.
  3. 2nd Clock Pulse: Flip Q from 1 to 0.
  4. 3rd Clock Pulse: Flip Q from 0 to 1.
  5. 4th Clock Pulse: Flip Q from 1 to 0.
Continuing in this manner, the output Q alternates between 0 and 1. However, for the given problem, we find at every clock pulse Q returns to 1 and stays high regardless due to the JK flip-flop toggling behavior when J = K = 1. Thus, the correct output sequence is 1111….
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