In the given circuit, the magnitude of VL and VC are twice that of VR. Given that f = 50 Hz, the inductance of the coil is \(\frac{1}{(K\pi)} \text{mH}\). The value of K is ________.
Solution and Explanation
VL = 2VR
So ωLi = 2 Ri
⇒L=\(\frac{2R}{ω}\)=\(\frac{2×5}{2π×50}\)=\(\frac{1}{10π}H\)
⇒\(\frac{100}{π}H\)
So
K=\(\frac{1}{100}\)≃0
So, value of K is 0
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JEE Main Notification
Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter