Question

In the following figure, the equivalent resistance between ‘A’ and ‘B’ will be

• A. 12 \(\Omega\)
• B. 5 \(\Omega\)
• C. 2.25 \(\Omega\)
• D. 1.2 \(\Omega\)

Hint:

When resistors are in series, add their resistances, and when in parallel, use the formula \(\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2}\).

Answer 1

The Correct Option is B

The resistances of 3 \(\Omega\) and 6 \(\Omega\) are in series. So, the total resistance is: \[ R_{\text{total}} = 3 \, \Omega + 6 \, \Omega = 9 \, \Omega \] Now, the total resistance of the series combination is in parallel with the 3 \(\Omega\) resistor: \[ R_{\text{eq}} = \frac{9 \times 3}{9 + 3} = \frac{27}{12} = 2.25 \, \Omega \] Thus, the correct answer is 2.25 \(\Omega\).