Question

In the final examination, Bishnu scored 52% and Asha scored 64%. The marks obtained by Bishnu is 23 less, and that by Asha is 34 more than the marks obtained by Ramesh. The marks obtained by Geeta, who scored 84%, is

• A. 439
• B. 399
• C. 357
• D. 417

Answer 1

The Correct Option is B

To solve the problem, we need to find the total marks of the examination and the marks obtained by Geeta. Let's denote the total marks by "T".

First, let's find the marks obtained by Ramesh, Bishnu, and Asha:

1. Bishnu scored 52%:
   • \( \text{Bishnu's marks} = \frac{52}{100} \times T \) 
2. Asha scored 64%:
   • \( \text{Asha's marks} = \frac{64}{100} \times T \)
3. According to the problem, Bishnu's marks are 23 less than Ramesh's marks:
   • \( \frac{52}{100} \times T = R - 23 \)
   • \( R = \frac{52}{100} \times T + 23 \)
4. Asha's marks are 34 more than Ramesh's marks:
   • \( \frac{64}{100} \times T = R + 34 \)
   • \( R = \frac{64}{100} \times T - 34 \)

Equating the two expressions for R, we have:

\( \frac{52}{100} \times T + 23 = \frac{64}{100} \times T - 34 \)

Solving for T:

\( \frac{64}{100} \times T - \frac{52}{100} \times T = 23 + 34 \)

\( \frac{12}{100} \times T = 57 \)

\( T = \frac{57 \times 100}{12} = 475 \)

Now, we have the total marks \( T = 475 \).

To find Geeta's marks, who scored 84%:

\( \text{Geeta's marks} = \frac{84}{100} \times 475 \)

\( = 399 \)

Therefore, the marks obtained by Geeta is 399.

Geeta's Marks

399

Answer 2

Let total marks be \(100x\). 

Marks obtained by Bishnu = \(52x\)
Marks obtained by Asha = \(Mx\)
Marks obtained by Ramesh = \(52x + 23\)
Marks obtained by Ramesh (another expression) = \(64x - 34\)

Equating both expressions for Ramesh's marks:
\(52x + 23 = 64x - 34\)
\(64x - 52x = 34 + 23\)
\(12x = 57\)
\(x = \frac{57}{12} = \frac{19}{4}\)

Marks obtained by Geeta = \(84x = 84 \times \frac{19}{4} = 21 \times 19 = 399\)
So, the correct option is (B): \(399\)