Question:

In the circuit shown, the ideality factor \( \eta \) of the diode is unity and the voltage drop across it is 0.7 V. The dynamic resistance of the diode at room temperature is approximately:
the ideality factor η of the diode is unity and the voltage drop across

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Dynamic resistance of a diode: \( r_d = \frac{V_T}{I_D} \), where \( V_T \approx 25\ \text{mV} \) at room temperature.
Updated On: June 02, 2025
  • \(15\ \Omega\)
  • \(25\ \Omega\)
  • \(50\ \Omega\)
  • \(700\ \Omega\)
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The Correct Option is B

Solution and Explanation

Dynamic resistance of a diode is given by: \[ r_d = \dfrac{\eta V_T}{I} \] Where: - \( \eta = 1 \) (ideality factor),
- \( V_T = 25\ \text{mV} = 0.025\ \text{V} \) at room temperature,
- Current \( I = \dfrac{1.7 - 0.7}{1000} = \dfrac{1}{1000} = 1\ \text{mA} \)
So: \[ r_d = \dfrac{0.025}{0.001} = 25\ \Omega \]
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