Question:

In the circuit shown in the figure, the current through

Updated On: Jul 31, 2023
  • the $3\Omega$ resistor is 0.50 A
  • the $3\Omega$ resistor is 0.25 A
  • the $4\Omega$ resistor is 0.50 A
  • the $4\Omega$ resistor is 0.25 A
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The Correct Option is D

Solution and Explanation

Net resistance of the circuit is $9\Omega.$
$\therefore$ Current drawn from the battery. = current through $3\Omega$ resistor
Potential difference between A and B is
$V_A-V_B=9-1(3+2)=4V=8i_1$
$\therefore i_1=0.5A$
$\therefore i_2=1-i_1=0.5A$
Similarly, potential difference between C and D
$V_C-V_D=(V_A-V_B)-i_2(2+2)$
$4-4i_2=4-4(0.5)=2V=8i_3$
$\therefore i_3=0.25A$
Therefore, $i_4=i_2-i_3=0.5-0.25$
$i_4=0.25A$
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Concepts Used:

Current Electricity

Current electricity is defined as the flow of electrons from one section of the circuit to another.

Types of Current Electricity

There are two types of current electricity as follows:

Direct Current

The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.

Alternating Current

The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.