In solid state, PCl5 forms an ionic compound. The phosphorus atom (P) has an empty 3d orbital and can expand its octet to form a compound with more than four bonds. In PCl5, it forms five bonds with chlorine atoms, but in the solid state, it forms an ionic compound by losing one electron to form a cation [PCl4]+ and gaining an electron to form an anion [PCl6]-.
Why is option (C) correct?
Why are the other options incorrect?
Conclusion: The correct answer is (C) Ionic solid with [PCl4]+ and [PCl6]- because PCl5 forms an ionic compound in the solid state with these specific ions.
In the solid state, PCl₅ exhibits ionic character and forms a crystal structure in which it dissociates into ions. The structure of PCl₅ in the solid state consists of both \( [PCl_4]^+ \) and \( [PCl_6]^- \) ions.
Option A (Octahedral structure)**: This is incorrect because PCl₅ in its solid state does not adopt an octahedral structure.
Option B (Ionic solid with \( [PCl_6]^+ \) and \( [PCl_4]^- \))**: This is incorrect because the charges on the ions are reversed.
Option C (Ionic solid with \( [PCl_4]^+ \) and \( [PCl_6]^- \))**: This is correct. In the solid-state structure of PCl₅, it exists as an ionic solid with these ions.
Option D (Covalent solid present in the form of \( P_2Cl_{10} \))**: This is incorrect because PCl₅ in the solid state exists as ionic solids, not covalent molecules like \( P_2Cl_{10} \).
Thus, the correct answer is: \({\text{(C) Ionic solid with } [PCl_4]^+ \text{ and } [PCl_6]^-}\)