Question:

In quantitative analysis of second group in lab. \(H_2S\) gas is passed in acidic medium for ppt. When \(Cu^{+2}\) and \(Cd^{+2}\) react with \(KCN\), than in which of the following condition, ppt will not be formed due to relative stability:

Updated On: Apr 18, 2024
  • \(K_2[Cu(CN)_4] – More\  stable\)
    \(K_2[Cd(CN)_4] – Less \ stable\)

  • \(K_2[Cu(CN)_4] – Less \ stable\)
    \(K_2[Cd(CN)_4] – More\  stable\)

  • \(K_3[Cu(CN)_4] – More\  stable\)
    \(K_2[Cd(CN)_4] – Less \ stable\)

  • \(K_3[Cu(CN)_4] – Less\  stable\)
    \(K_3[Cd(CN)_4] – More \ stable\)

Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

\(K_3[Cu(CN)_4]\) is more stable than \(K_2[Cd(CN)_4]\), which means that the complex with \(Cu^{2+}\) is more stable and less likely to precipitate compared to the complex with \(Cd^{2+}\)

So, the correct option is (C): \(K_3[Cu(CN)_4] – More\  stable\)\(K_2[Cd(CN)_4] – Less \ stable\)

Was this answer helpful?
0
0

Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.