Question:

In producing chlorine through electrolysis $100\, W$ power at $125\, V$ is being consumed. How much chlorine per minute is leberated? ($ECE$ of chlorine is $0.367 ? 10^{-6}\, kg/C$)

Updated On: Apr 26, 2024
  • $24.3\,mg$
  • $16.6\,mg$
  • $17.6\,mg$
  • $21.3\,mg$
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The Correct Option is D

Solution and Explanation

$P=100\,W$ and $V=125\,V$
$P=VI \Rightarrow I=\frac{P}{V}=\frac{100}{125}A$
Mass of chlorine liberated = zit
$=0.367\times10^{-6}\times\frac{100}{125}\times60$
$=17.6\,mg$
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Concepts Used:

Electrolysis

Electrolysis:

Electrolysis is the process by which an element is decomposed and undergoes some chemical change under the influence of any electric current. The first-ever electrolysis was executed out by Sir Humphrey Davey in the year 1808. Electrolysis can occur in both Galvanic cells and Electrolytic cells

Applications of Electrolysis:

  1. Electrolytic cells are used for the production of Hydrogen and Oxygen gas from water.
  2. They are used for the large-scale production of pure metals like sodium, copper, magnesium, etc.
  3. They are used to extract Aluminium from Bauxite.
  4. Electrolytic cells are used for electroplating, a process by which a thin protective layer of one metal is formed over another metal, mostly for protection.
  5. Electrolysis is used for the electrorefining of non-ferrous metals.

Read More: Products of Electrolysis