In April, John spent ₹450 on rice. The price of rice increased by 20% in May.
April cost = ₹450
Percentage increase = 20%
May cost for rice: \[ 450 + \frac{20}{100} \times 450 = 450 + 90 = ₹540 \]
In May, wheat price increased by 12%.
So May cost of wheat: \[ x + 0.12x = 1.12x \]
April total = ₹450 (rice) + ₹x (wheat) = ₹(450 + x)
May total = ₹540 (rice) + ₹1.12x (wheat) = ₹(540 + 1.12x)
Given: \[ (540 + 1.12x) - (450 + x) = 150 \] Simplify: \[ 540 + 1.12x - 450 - x = 150 \] \[ 90 + 0.12x = 150 \Rightarrow 0.12x = 60 \Rightarrow x = \frac{60}{0.12} = 500 \]
\[ 1.12x = 1.12 \times 500 = ₹560 \]
Let John buy \( m \) kg of rice and \( p \) kg of wheat.
If price of rice in April is \( r \), then price in May is \( 1.2r \).
If price of wheat in April is \( w \), then price in May is \( 1.12w \).
It is given that John spent ₹150 more in May than in April.
When $10^{100}$ is divided by 7, the remainder is ?