Question:

In Lassaigne’s test for nitrogen in an organic compound, the Prussian blue color is obtained due to the formation of 

Updated On: Jan 19, 2026
  • \(Na_4[Fe(CN)_6]\)

  • \(Fe_4[Fe(CN)_6]_3\) 

  • \(Fe_2[Fe(CN)_6]\)

  • \(Fe_3[Fe(CN)_6]_4\)

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The Correct Option is B

Solution and Explanation

In Lassaigne’s test, the presence of nitrogen in an organic compound is detected by converting it into sodium cyanide (\text{NaCN}). This is done by fusing the organic compound with sodium in a fusion tube. When water is added, the following reaction occurs:

\text{Na} + \text{C} + \frac{1}{2}\text{N}_2 \rightarrow \text{NaCN}

To confirm the presence of nitrogen, the resulting solution is treated with ferrous sulfate (\text{FeSO}_4) and then heated. During this step, ferrous cyanide (\text{Fe(CN)}_2) is formed:

6\text{NaCN} + \text{FeSO}_4 \rightarrow \text{Na}_4[\text{Fe(CN)}_6] + \text{Na}_2\text{SO}_4

Upon further treatment with ferric chloride (\text{FeCl}_3), 'Prussian blue', which is ferric ferrocyanide, is formed. The relevant reaction is:

3\text{Na}_4[\text{Fe(CN)}_6] + 4\text{FeCl}_3 \rightarrow \text{Fe}_4[\text{Fe(CN)}_6]_3 + 12\text{NaCl}

The compound \text{Fe}_4[\text{Fe(CN)}_6]_3 is responsible for the characteristic Prussian blue color. This confirms the presence of nitrogen in the organic compound.

Let's analyze why \text{Fe}_4[\text{Fe(CN)}_6]_3 is the correct answer:

  • \text{Na}_4[\text{Fe(CN)}_6] is not the Prussian blue complex but a precursor (sodium ferrocyanide).
  • \text{Fe}_2[\text{Fe(CN)}_6] is not a standard compound related to the traditional Lassaigne's test for nitrogen.
  • \text{Fe}_3[\text{Fe(CN)}_6]_4 is not the Prussian blue complex and does not form under these conditions.

Thus, the compound responsible for the Prussian blue color in Lassaigne's test is \text{Fe}_4[\text{Fe(CN)}_6]_3.

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Concepts Used:

Organic Chemistry – Some Basic Principles and Techniques - Reaction Mechanism

SN1 Reaction Mechanism:

SN1 reaction mechanism takes place by following three steps –

  • Formation of carbocation 
  • Attack of nucleophile 
  • Deprotonation 

SN2 Reaction Mechanism:

The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.

Electrophilic Aromatic Substitution Reaction Mechanism:

The mechanism of an electrophilic aromatic substitution reaction contains three main components which are:

  1. A new sigma bond from C=C is formed during the reaction in the arene nucleophile.
  2. Due to the breaking of the C-H sigma bond, a proton is removed.
  3. The C=C bond is reformed and it restores the aromaticity of the compound.

Electrophilic Substitution Reaction Mechanism:

The electrophilic substitution reaction mechanism is composed of three steps, which will be discussed more below.

  • Electrophile Generation
  • Carbocation Formation
  • Proton Removal