\(Na_4[Fe(CN)_6]\)
\(Fe_4[Fe(CN)_6]_3\)
\(Fe_2[Fe(CN)_6]\)
\(Fe_3[Fe(CN)_6]_4\)
In Lassaigne’s test, the presence of nitrogen in an organic compound is detected by converting it into sodium cyanide (\text{NaCN}). This is done by fusing the organic compound with sodium in a fusion tube. When water is added, the following reaction occurs:
\text{Na} + \text{C} + \frac{1}{2}\text{N}_2 \rightarrow \text{NaCN}
To confirm the presence of nitrogen, the resulting solution is treated with ferrous sulfate (\text{FeSO}_4) and then heated. During this step, ferrous cyanide (\text{Fe(CN)}_2) is formed:
6\text{NaCN} + \text{FeSO}_4 \rightarrow \text{Na}_4[\text{Fe(CN)}_6] + \text{Na}_2\text{SO}_4
Upon further treatment with ferric chloride (\text{FeCl}_3), 'Prussian blue', which is ferric ferrocyanide, is formed. The relevant reaction is:
3\text{Na}_4[\text{Fe(CN)}_6] + 4\text{FeCl}_3 \rightarrow \text{Fe}_4[\text{Fe(CN)}_6]_3 + 12\text{NaCl}
The compound \text{Fe}_4[\text{Fe(CN)}_6]_3 is responsible for the characteristic Prussian blue color. This confirms the presence of nitrogen in the organic compound.
Let's analyze why \text{Fe}_4[\text{Fe(CN)}_6]_3 is the correct answer:
Thus, the compound responsible for the Prussian blue color in Lassaigne's test is \text{Fe}_4[\text{Fe(CN)}_6]_3.


Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.
SN1 reaction mechanism takes place by following three steps –
The SN2 reaction mechanism involves the nucleophilic substitution reaction of the leaving group (which generally consists of halide groups or other electron-withdrawing groups) with a nucleophile in a given organic compound.
The mechanism of an electrophilic aromatic substitution reaction contains three main components which are:
The electrophilic substitution reaction mechanism is composed of three steps, which will be discussed more below.