Question

In Haber’s process of manufacture of ammonia, the ‘catalyst’, the ‘promoter’, and‘ poison for the catalyst’ are respectively:

• A. \( Fe, W, CO \)
• B. \( Co, Mo, CO \)
• C. \( Fe, Mo, CO_2 \)
• D. \( Fe, Mo, CO \)

Hint:

In the Haber process, iron (\( Fe \)) is used as the catalyst, molybdenum (\( Mo \)) as a promoter, and carbon monoxide (\( CO \)) acts as a catalyst poison, reducing efficiency by adsorbing on the catalyst surface.

Answer 1

The Correct Option is D

Step 1: Understanding the Haber Process 
The Haber process is used for the industrial production of ammonia (\( NH_3 \)) from nitrogen (\( N_2 \)) and hydrogen (\( H_2 \)) under high pressure and temperature. The reaction is: \[ N_2 + 3H_2 \rightleftharpoons 2NH_3 \] 

Step 2: Identifying the Catalyst, Promoter, and Poison 
- Catalyst: Iron (\( Fe \)) is used as the main catalyst to increase the rate of reaction.
- Promoter: Molybdenum (\( Mo \)) is added as a promoter to enhance the efficiency of iron as a catalyst.
- Poison for the Catalyst: Carbon monoxide (\( CO \)) acts as a poison for the iron catalyst by adsorbing on its active sites and deactivating it.
Step 3: Evaluating the Given Options 
- Option (1): Incorrect, as tungsten (\( W \)) is not used in the Haber process.
- Option (2): Incorrect, as cobalt (\( Co \)) is not the main catalyst.
- Option (3): Incorrect, as \( CO_2 \) is not the primary catalyst poison.
- Option (4): Correct, as the correct catalyst is \( Fe \), the promoter is \( Mo \), and the poison is \( CO \).
Thus, the correct answer is 

Option (4).