In an FCC unit cell, atoms are present at the 8 corners of the cube (each contributing \(1/8\) atom) and at the centers of all 6 faces (each contributing \(1/2\) atom). The total number of lattice points is:
\[\text{Total} = 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 1 + 3 = 4\]