Let:
We are told that the number of unattempted questions \(U\) is greater than the number of attempted questions \((C + W)\), so \(U > C + W\).
From the equations above, we can solve for \(U\) in terms of \(C\):
\(U = 97 - 3C + W\)
\(97 - 3C + W > C + W\)
Now simplify:
\(97 - 3C > C\)
Subtracting \(C\) from both sides:
\(97 > 4C\)
Dividing by 4:
\(C < 24.25\)
Since the number of correct answers \((C)\) must be a whole number, the maximum possible value for \(C\) is 24.
The maximum number of correct answers Rayan could have given in the examination is 24.
Let’s assume the following:
\((2) - (1) \Rightarrow x - y = 11\)
\((1) + (2) \Rightarrow 2x + z = 86\)
\(z > x + y\)
\(z > 75 - z\)
\(z > 37.5\)
From the above equation, the minimum possible value of \(z\) is 38.
\(2x + 38 = 86\)
\(2x = 48\)
\(x = 24\)
Therefore, the maximum number of correct questions solved is 24.
When $10^{100}$ is divided by 7, the remainder is ?