The correct answer is :24
Let's break down the information given in the problem:
Correct answers:+3 marks
Wrong answers: -1 mark
Unattempted questions:+1 mark
Let's denote the following variables:
C: Number of correct answers
W: Number of wrong answers
U: Number of unattempted questions
We are given the following information:
C+W+U=75(total questions)
3C-W+U=97(total marks)
We also know that U(unattempted questions) is greater than the number of attempted questions(C+W),so U>C+W.
We need to find the maximum value of C(number of correct answers).
From the equations above, we can solve for U in terms of C:
U=97-3C+W
Since U>C+W,we can substitute the value of U:
97-3C+W>C+W
Simplify:
97-3C>C
Subtract C from both sides:
97>4C
Divide by 4:
C<24.25
Since the number of correct answers (C) must be a whole number,the maximum possible value for C is 24.
Therefore,the maximum number of correct answers Rayan could have given in the examination is 24.