Given that group B contains 23 questions, the total number of questions is 100. Let the number of questions in group A be \(x\) and in group C be \(y\). We know:
\[
x + 23 + y = 100 \quad \text{or} \quad x + y = 77
\]
Also, the total marks from group A are at least 60% of the total marks. The total marks from each group are:
- Group A: \(x \times 1\)
- Group B: \(23 \times 2 = 46\)
- Group C: \(y \times 3\)
The total marks are \(x + 46 + 3y\), and this must be at least 60% of the total marks, i.e.:
\[
x + 46 + 3y \geq 0.6 \times 100 = 60
\]
This gives the equation:
\[
x + 3y \geq 14
\]
Since \(x + y = 77\), solving these two equations gives a range for \(y\), but the exact value cannot be determined. Therefore, the answer is (4) Cannot be determined.
\[
\boxed{\text{Cannot be determined}}
\]