Let A and B be the events of passing first and second examinations respectively.
Accordingly, P(A) = 0.8, P(B) = 0.7 and P (A or B) = 0.95
We know that P (A or B) = P(A) + P(B) - P (A and B)
∴ 0.95 = 0.8 + 0.7 - P (A and B)
\(⇒\)P (A and B) = 0.8 + 0.7 - 0.95 = 0.55
Thus, the probability of passing both the examinations is 0.55.
| P(A) | P(B) | P(A∩B) | P(A∪B) | |
| (i) | \(\frac{1}{3}\) | \(\frac{1}{5}\) | \(\frac{1}{15}\) | … |
| (ii) | 0.35 | …. | 0.25 | 0.6 |
| (iii) | 0.5 | 0.35 | …. | 0.7 |
Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.
The axiomatic probability perspective is a unifying perspective in which the coherent conditions used in theoretical and experimental probability exhibit subjective probability. Kolmogorov's set of rules or axioms is put to all types of probability. They are known as Kolmogorov's 3 axioms by mathematicians. You can use axiomatic probability to calculate the likelihood of an event that is occurring or not occurring.
The 3 axioms are applicable to all other probability perspectives. This viewpoint is defined as the probability of any function from numbers to events that are satisfied by the three axioms listed below:
