Question:

In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be:

Updated On: May 22, 2024
  • \(\frac{499}{500}G\)
  • \(\frac{1}{500}G\)
  • \(\frac{500}{499}G\)
  • \(\frac{1}{499}G\)
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The Correct Option is B

Solution and Explanation

The correct option (B): \(\frac{1}{500}G\)
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