Question:

In an ac circuit , an alternating voltage $e = 200 \sqrt2 \,sin \,100\, t$ volts is connected to a capacitor of capacitance $1 \,\mu \,F$. The rms value of the current in the circuit is :

Updated On: May 5, 2024
  • 10 mA
  • 100 mA
  • 200 mA
  • 20 mA
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The Correct Option is D

Solution and Explanation

given $e =200 \sqrt{2} \sin 100 t$
$\omega=100 \frac{ rad }{ sec }$
$E _{ rms }=\frac{200 \sqrt{2}}{\sqrt{2}}$
$C =1 \times 10^{-6}$
$Z = X _{ c }=\frac{1}{\omega C }=\frac{1}{100 \times 10^{-6}}=10^{4} \Omega$
$I =\frac{ E _{ rms }}{ Z }=\frac{\frac{200 \sqrt{2}}{\sqrt{2}}}{10^{4}}=2 \times 10^{-2} A =20 mA$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter