Question:
In alkaline medium, \( \text{MnO}_4^- \) oxidizes \( \text{I}^- \) to:
In alkaline medium, \( \text{MnO}_4^- \) oxidizes \( \text{I}^- \) to:
Updated On: Nov 13, 2024
- \( \text{IO}_4^- \)
- \( \text{IO}^- \)
- \( \text{I}_2 \)
- \( \text{IO}_3^- \)
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The Correct Option is D
Solution and Explanation
The reaction of MnO4- in an alkaline medium with I- produces IO3- as the product.
2MnO4- + H2O + I- → 2MnO2 + 2OH- + IO3-
Thus, the oxidation of I- in the presence of MnO4- under alkaline conditions leads to the formation of IO3-.
So, the correct answer is : Option (4)
2MnO4- + H2O + I- → 2MnO2 + 2OH- + IO3-
Thus, the oxidation of I- in the presence of MnO4- under alkaline conditions leads to the formation of IO3-.
So, the correct answer is : Option (4)
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