Question:

In a year, out of 160 games to be played, a cricket team wants to win 80% of them. Out of 90 games already played, the success rate is \( 66 \frac{2}{3} \)% . What should be the success rate for the remaining games in order to reach the target?

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When calculating percentage success, always break the problem into smaller parts, such as finding how many games the team needs to win, and calculate the success rate for the remaining games.
Updated On: Apr 19, 2025
  • \( 84 \frac{5}{7} \)%
  • \( 85 \frac{1}{3} \)%
  • \( 93 \frac{2}{3} \)%
  • \( 97 \frac{1}{7} \)%
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The Correct Option is D

Solution and Explanation

We are given that the team wants to win 80% of the 160 games, which is: \[ 80% \text{ of } 160 = 0.8 \times 160 = 128 \text{ games} \] Out of the 90 games already played, the team won \( 66 \frac{2}{3} \)% of them. Converting the percentage: \[ 66 \frac{2}{3} % = \frac{200}{3} % = \frac{200}{3} \times 90 = 6000 / 3 = 200 \text{ games} \] So, the team has already won 60 games. To reach the target of 128 games, they need to win: \[ 128 - 60 = 68 \text{ games} \] There are 70 games left to be played, so the required success rate for the remaining games is: \[ \frac{68}{70} \times 100 = 97 \frac{1}{7} % \] Thus, the required success rate for the remaining games is \( 97 \frac{1}{7} \)%.
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