Given:
Step 1: Let the number of males and females in the village be:
Step 2: Literate males and females are in the ratio $2:3$.
Let the common multiple be $y$, then:
Step 3: Given that literate males = 3600
So, $2y = 3600 \Rightarrow y = 1800$
Thus:
Step 4: Now consider illiterate males and females in the ratio $4:3$.
Let the common multiple be $z$, then:
Step 5: Total males = literate males + illiterate males
$5x = 2y + 4z = 3600 + 4z$
Step 6: Total females = literate females + illiterate females
$4x = 3y + 3z = 5400 + 3z$
Now, solve for $x$ using either equation:
From Step 5: $5x = 3600 + 4z \Rightarrow x = \frac{3600 + 4z}{5}$
From Step 6: $4x = 5400 + 3z \Rightarrow x = \frac{5400 + 3z}{4}$
Equating both expressions for $x$:
$\frac{3600 + 4z}{5} = \frac{5400 + 3z}{4}$
Cross-multiply:
$4(3600 + 4z) = 5(5400 + 3z)$
$14400 + 16z = 27000 + 15z$
$16z - 15z = 27000 - 14400$
$z = 12600$
Now find $x$:
$x = \frac{3600 + 4 \times 12600}{5} = \frac{3600 + 50400}{5} = \frac{54000}{5} = 10800$
Total number of females = $4x = 4 \times 10800 = \boxed{43200}$
Given: The ratio of literate males to literate females is 2 : 3.
Number of literate males = 3600
Using the ratio, we calculate the number of literate females:
Literate females = \(\frac{3600}{2} \times 3 = 5400\)
Also given: The male to female ratio in the village is 5 : 4.
Let the total number of males be \(5y\) and total number of females be \(4y\).
Then, illiterate males = \(5y - 3600\)
and illiterate females = \(4y - 5400\)
Given that the ratio of illiterate males to illiterate females is 4 : 3, we write:
\(\frac{5y - 3600}{4y - 5400} = \frac{4}{3}\)
Cross-multiplying:
\(3(5y - 3600) = 4(4y - 5400)\)
\(15y - 10800 = 16y - 21600\)
\(y = 10800\)
Total number of females:
\(4y = 4 \times 10800 = \mathbf{43200}\)
Final Answer: ₹43,200
When $10^{100}$ is divided by 7, the remainder is ?