Question:

In a trapezium ABCD, AB is parallel to DC, BC is perpendicular to DC and \(∠BAD=45°\). If DC=5cm , BC=4 cm, the area of the trapezium in sq cm is ? [This Question was asked as TITA]

Updated On: Jul 8, 2024
  • \(25 \ cm^2\)

  • \(26 \ cm^2\)

  • \(28\  cm^2\)

  • \(30\ cm^2\)

Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Dropping a perpendicular \(DE\) onto \(AB\), the figure is divided into two parts - a rectangle of dimensions \(4×5\) and an isosceles triangle \(AED\).

Required answer = \(\text{Area of rectangle} + \text{Area of triangle}\) 

\(4×5+\frac{1}{2}(4×4)=28\;cm^2\)

Was this answer helpful?
0
0

Questions Asked in CAT exam

View More Questions