\(25 \ cm^2\)
\(26 \ cm^2\)
\(28\ cm^2\)
\(30\ cm^2\)
Dropping a perpendicular \(DE\) onto \(AB\), the figure is divided into two parts - a rectangle of dimensions \(4×5\) and an isosceles triangle \(AED\).
Required answer = \(\text{Area of rectangle} + \text{Area of triangle}\)
= \(4×5+\frac{1}{2}(4×4)=28\;cm^2\)