Question:
In a trapezium ABCD, AB is parallel to DC, BC is perpendicular to DC and \(∠BAD=45°\). If DC=5cm , BC=4 cm, the area of the trapezium in sq cm is ? [This Question was asked as TITA]
In a trapezium ABCD, AB is parallel to DC, BC is perpendicular to DC and \(∠BAD=45°\). If DC=5cm , BC=4 cm, the area of the trapezium in sq cm is ? [This Question was asked as TITA]
Updated On: Jul 8, 2024
\(25 \ cm^2\)
\(26 \ cm^2\)
\(28\ cm^2\)
\(30\ cm^2\)
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The Correct Option is C
Solution and Explanation
Dropping a perpendicular \(DE\) onto \(AB\), the figure is divided into two parts - a rectangle of dimensions \(4×5\) and an isosceles triangle \(AED\).
Required answer = \(\text{Area of rectangle} + \text{Area of triangle}\)
= \(4×5+\frac{1}{2}(4×4)=28\;cm^2\)
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