Given that, initially number of matches team has played =40
The number of matches won by team =30% of 40=\(\frac{30}{100}×40\)=12
Let the remaining matches be x.
The number of remaining matches won by team =60% of
\(x=\frac{60}{100}× x=0.06x\)
simplifies :
\(=12+1.2x=40+x\)
\(=0.2x=16\)
\(=x=\frac{16}{0.2}\)
\(x=80\)
When the team won 90% of the remaining matches.
Then, the number of remaining matches won by the team 90% of
\(80=\frac{90}{100}×80=72\)
The total number of matches won by the team in the tournament
\(=12+72=84\)
so, correct answer is: 84.
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: